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Iron objects such as storage tanks and underground pipelines can be protected from corrosion by connecting them through a wire to a piece of


A) Pb.
B) Ag.
C) Sn.
D) Mg.
E) Cu.

F) All of the above
G) A) and B)

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Consider the following redox equation. Mn(OH) 2(s) + MnO4-(aq) → MnO42-(aq) (basic solution) When the equation is balanced with the smallest whole number coefficients,what is the coefficient for OH-(aq) and on which side of the equation is OH-(aq) present?


A) 4,reactant side
B) 4,product side
C) 6,reactant side
D) 6,product side
E) 8,reactant side

F) C) and D)
G) A) and E)

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The voltaic cell composed of Co(s) ,Co2+(aq) ,Cu(s) ,and Cu2+(aq) has E°cell = 0.62 V.If E° of the cathode half-cell is 0.34 V,what is E° of the anode half-cell? Cu2+(aq) + Co(s) → Cu(s) + Co2+(aq)


A) -0.28 V
B) -0.96 V
C) 0.28 V
D) 0.96 V
E) 0.21 V

F) All of the above
G) A) and E)

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What would you observe if you set up the following electrochemical cell: Ag|AgNO3(0.001 M) ||AgNO3(1 M) |Ag?


A) Electrons will flow from left to right,causing a decrease in the AgNO3 concentration in the left cell,and an increase in the AgNO3 concentration in the right cell.
B) Electrons will flow from right to left,causing an increase in the AgNO3 concentration in the left cell,and a decrease in the AgNO3 concentration in the right cell.
C) Electrons will flow from left to right,causing an increase in the AgNO3 concentration in the left cell,and a decrease in AgNO3 concentration in the right cell.
D) Electrons will flow from right to left,causing a decrease in the AgNO3 concentration in the left cell,and an increase in the AgNO3 concentration in the right cell.
E) There will be no electron flow because the reduction potential at both electrodes is the same.

F) None of the above
G) A) and B)

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In the electrolyte of an electrochemical cell,current is carried by electrons moving from the anode to the cathode.

A) True
B) False

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A cell can be prepared from copper and tin.What is the E°cell for the galvanic cell that forms from the following half-reactions? Cu2+(aq) + 2e- A cell can be prepared from copper and tin.What is the E°<sub>cell</sub> for the galvanic cell that forms from the following half-reactions? Cu<sup>2+</sup>(aq) + 2e<sup>-</sup>   Cu(s) E° = 0.34V Sn<sup>4+</sup>(aq) + 2e<sup>-</sup>   Sn<sup>2+</sup>(aq) E° = 0.13V A) 0.47 V B) 0.21 V C) -0.21 V D) -0.47 V E) 0.42 V Cu(s) E° = 0.34V Sn4+(aq) + 2e- A cell can be prepared from copper and tin.What is the E°<sub>cell</sub> for the galvanic cell that forms from the following half-reactions? Cu<sup>2+</sup>(aq) + 2e<sup>-</sup>   Cu(s) E° = 0.34V Sn<sup>4+</sup>(aq) + 2e<sup>-</sup>   Sn<sup>2+</sup>(aq) E° = 0.13V A) 0.47 V B) 0.21 V C) -0.21 V D) -0.47 V E) 0.42 V Sn2+(aq) E° = 0.13V


A) 0.47 V
B) 0.21 V
C) -0.21 V
D) -0.47 V
E) 0.42 V

F) D) and E)
G) C) and D)

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What is E°cell for the following reaction,and is it spontaneous or nonspontaneous under standard-state conditions? 2Fe3+(aq) + 2H2O(l) → H2O2(aq) + 2H+(aq) + 2Fe2+(aq) Given: H2O2(aq) + 2H+(aq) + 2e- What is E°<sub>cell</sub> for the following reaction,and is it spontaneous or nonspontaneous under standard-state conditions? 2Fe<sup>3+</sup>(aq) + 2H<sub>2</sub>O(l) → H<sub>2</sub>O<sub>2</sub>(aq) + 2H<sup>+</sup>(aq) + 2Fe<sup>2+</sup>(aq)  Given: H<sub>2</sub>O<sub>2</sub>(aq) + 2H<sup>+</sup>(aq) + 2e<sup>-</sup> <sup> </sup>   2H<sub>2</sub>O(l) E° = 1.77V Fe<sup>3+</sup>(aq) + e<sup>-</sup>   Fe<sup>2+</sup>(aq) E° = 0.77V A) E°<sub>cell</sub> = -1.00 V,nonspontaneous B) E°<sub>cell</sub> = -1.00 V,spontaneous C) E°<sub>cell</sub> = 1.00 V,nonspontaneous D) E°<sub>cell</sub> = 1.00 V,spontaneous E) E°<sub>cell</sub> = -0.23 V,nonspontaneous 2H2O(l) E° = 1.77V Fe3+(aq) + e- What is E°<sub>cell</sub> for the following reaction,and is it spontaneous or nonspontaneous under standard-state conditions? 2Fe<sup>3+</sup>(aq) + 2H<sub>2</sub>O(l) → H<sub>2</sub>O<sub>2</sub>(aq) + 2H<sup>+</sup>(aq) + 2Fe<sup>2+</sup>(aq)  Given: H<sub>2</sub>O<sub>2</sub>(aq) + 2H<sup>+</sup>(aq) + 2e<sup>-</sup> <sup> </sup>   2H<sub>2</sub>O(l) E° = 1.77V Fe<sup>3+</sup>(aq) + e<sup>-</sup>   Fe<sup>2+</sup>(aq) E° = 0.77V A) E°<sub>cell</sub> = -1.00 V,nonspontaneous B) E°<sub>cell</sub> = -1.00 V,spontaneous C) E°<sub>cell</sub> = 1.00 V,nonspontaneous D) E°<sub>cell</sub> = 1.00 V,spontaneous E) E°<sub>cell</sub> = -0.23 V,nonspontaneous Fe2+(aq) E° = 0.77V


A) E°cell = -1.00 V,nonspontaneous
B) E°cell = -1.00 V,spontaneous
C) E°cell = 1.00 V,nonspontaneous
D) E°cell = 1.00 V,spontaneous
E) E°cell = -0.23 V,nonspontaneous

F) C) and D)
G) A) and C)

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What is the oxidizing agent in the (unbalanced) reaction? Cu(s) + H+(aq) + NO3-(aq) → NO(g) + H2O(l) + Cu2+(aq)


A) Cu
B) H+
C) NO3-
D) NO
E) Cu2+

F) B) and C)
G) A) and B)

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When the following redox equation is balanced with the smallest whole number coefficients,the coefficient for the hydrogen sulfate ion will be ______. Al(s) + HSO4-(aq) + OH-(aq) → Al2O3(s) + S2-(aq) + H2O(l)


A) 1
B) 3
C) 4
D) 6
E) 8

F) B) and D)
G) None of the above

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What is the equilibrium constant at 25°C for the following reaction? (R = 8.314 J/K • mol,F = 96,500 C • mol-1) Sn2+(aq) + Fe(s) What is the equilibrium constant at 25°C for the following reaction? (R = 8.314 J/K • mol,F = 96,500 C • mol<sup>-1</sup>)  Sn<sup>2+</sup>(aq) + Fe(s)    Sn(s) + Fe<sup>2+</sup>(aq) E°<sub>cell</sub> = 0.30V A) 1.2 × 10<sup>5</sup> B) 1.4 × 10<sup>10</sup> C) 8.6 × 10<sup>-6</sup> D) 7.1 × 10<sup>-11</sup> E) 2.3 × 10<sup>23</sup> Sn(s) + Fe2+(aq) E°cell = 0.30V


A) 1.2 × 105
B) 1.4 × 1010
C) 8.6 × 10-6
D) 7.1 × 10-11
E) 2.3 × 1023

F) A) and E)
G) A) and C)

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A voltaic cell consists of a Hg/Hg22+ electrode (E°= 0.85 V) and a Sn/Sn2+ electrode (E°= -0.14 V) .Calculate [Sn2+] if [Hg22+] = 0.24 M and Ecell = 1.04 V at 25°C.


A) 0.00010 M
B) 0.00070 M
C) 0.0049 M
D) 0.030 M
E) 0.050 M

F) A) and E)
G) C) and D)

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At equilibrium E° = 0.

A) True
B) False

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Complete and balance the following redox equation.When properly balanced using the smallest whole-number coefficients,the coefficient of S is H2S + HNO3 → S + NO + H2O (acidic solution)


A) 1.
B) 2.
C) 3.
D) 5.
E) 6.

F) C) and E)
G) C) and D)

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Complete and balance the following redox equation using the set of smallest whole numbers coefficients.What is the sum of the coefficients? HI + HNO3 → I2 + NO (acidic solution)


A) 5
B) 7
C) 14
D) 17
E) None of these choices is correct.

F) A) and B)
G) B) and D)

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The Faraday constant represents the charge of 1 mole of electrons.

A) True
B) False

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A salt bridge allows movement of cations and anions from one half-cell to the other.

A) True
B) False

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Based on the data presented below,which is the strongest reducing agent? E°(V) Al3+ + 3e- → Al(s) -1.66 AgBr(s) + e- → Ag(s) +Br- +0.07 Sn4+ + 2e- → Sn2+ +0.14 Fe3+ + e- → Fe2+ +0.77


A) Fe3+
B) Fe2+
C) Br-
D) Al3+
E) Al(s)

F) All of the above
G) A) and E)

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Based on the following electrochemical cell,what is the standard reduction potential of metal M at 298 K? Based on the following electrochemical cell,what is the standard reduction potential of metal M at 298 K?   Half-Reaction E° (V)  Ni<sup>2+</sup>(aq) + 2e<sup>-</sup> →Ni(s) -0.25 A) -1.40 V B) -0.80 V C) +0.25 V D) +0.80 V E) +1.40 V Half-Reaction E° (V) Ni2+(aq) + 2e- →Ni(s) -0.25


A) -1.40 V
B) -0.80 V
C) +0.25 V
D) +0.80 V
E) +1.40 V

F) A) and E)
G) B) and E)

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What is E°cell for a galvanic cell represented by the combination of the following half-reactions? ClO4-(aq) + 8 H+(aq) +8e- What is E°<sub>cell</sub> for a galvanic cell represented by the combination of the following half-reactions? ClO<sub>4</sub><sup>-</sup>(aq) + 8 H<sup>+</sup>(aq) +8e<sup>-</sup> <sup> </sup>   Cl<sup>-</sup>(aq) +4H<sub>2</sub>O(l) E° = 1.389V VO<sub>2</sub><sup>+</sup>(aq) + 2H<sup>+</sup>(aq) +e<sup>-</sup> <sup> </sup>   VO<sup>+</sup>(aq) +H<sub>2</sub>O(l) E° = 0.991V A) -0.398 V B) -2.380 V C) 0.398 V D) 2.380 V E) 6.539 V Cl-(aq) +4H2O(l) E° = 1.389V VO2+(aq) + 2H+(aq) +e- What is E°<sub>cell</sub> for a galvanic cell represented by the combination of the following half-reactions? ClO<sub>4</sub><sup>-</sup>(aq) + 8 H<sup>+</sup>(aq) +8e<sup>-</sup> <sup> </sup>   Cl<sup>-</sup>(aq) +4H<sub>2</sub>O(l) E° = 1.389V VO<sub>2</sub><sup>+</sup>(aq) + 2H<sup>+</sup>(aq) +e<sup>-</sup> <sup> </sup>   VO<sup>+</sup>(aq) +H<sub>2</sub>O(l) E° = 0.991V A) -0.398 V B) -2.380 V C) 0.398 V D) 2.380 V E) 6.539 V VO+(aq) +H2O(l) E° = 0.991V


A) -0.398 V
B) -2.380 V
C) 0.398 V
D) 2.380 V
E) 6.539 V

F) None of the above
G) All of the above

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What is the minimum voltage required for the electrolysis of 1.0 M NaCl in neutral solution? 2H2O + 2Cl- (1.0 M) → H2(1 atm) + Cl2(1 atm) + 2OH-(1 × 10-7 M) Note that 2H2O(l) + 2e- → H2(g) +2OH-(aq) ,E° = -0.83 V, 2H2O(l) + 2e- → H2(g) +2OH-(aq) ,E = -0.41 V([OH-] = 1 × 10-7M) , O2(g) + 4H+(aq) + 4e- →2H2O(l) ,E° = +1.23 V, Cl2(g) + 2e- → 2Cl-(aq) E° = +1.36 V,and Na+(aq) + e- → Na(s) E° = -2.71 V


A) 2.19 V
B) 1.77 V
C) 0.41 V
D) -0.41 V
E) -1.78 V

F) B) and D)
G) B) and E)

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