A) Because there are more atoms in acetone
B) Because there are more resonance structures for the enolate of acetone
C) It isn't; the allyl anion is less basic.
D) One of the resonance structures for the enolate places the negative charge on the more electronegative oxygen.
Correct Answer
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Multiple Choice
A) [1] Br2, CH3CO2H; [2] Li2CO3, LiBr, DMF; [3] CH3CH2CH2CH2Br
B) [1] Br2, CH3CO2H; [2] Mg, Et2O; [3] CH3CH2CH2CH2Br
C) [1] LDA; [2] BrCH2CH2CH2CH2Br; [3] NaOEt
D) [1] NaOEt; [2] BrCH2CH2CH2CH2Br; [3] LDA
Correct Answer
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Multiple Choice
A) I
B) II
C) III
D) IV
Correct Answer
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Multiple Choice
A) 3-Heptanone
B) 2-Pentanone
C) 3-Hexanone
D) Cyclohexanone
Correct Answer
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Multiple Choice
A) Because tert-butyl bromide is too basic.
B) Because tert-butyl bromide cannot undergo an SN2 reaction.
C) Because tert-butyl bromide is a nucleophile.
D) Because tert-butyl bromide is not a stable compound.
Correct Answer
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Multiple Choice
A) I
B) II
C) III
D) IV
Correct Answer
verified
Multiple Choice
A) Keep the reaction as cold as possible.
B) Use an aprotic solvent such as THF.
C) Use a protic solvent such as ethanol.
D) Use a carboxylic acid.
Correct Answer
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Multiple Choice
A) The ketone undergoes a Bayer-Villigar oxidation.
B) The ketone is reduced.
C) The ketone undergoes an Aldol reaction.
D) The bromine helps to stabilize the second enolate, making the product more acidic than the starting material.
Correct Answer
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Multiple Choice
A) I
B) II
C) III
D) IV
Correct Answer
verified
Multiple Choice
A) I
B) II
C) III
D) IV
Correct Answer
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Multiple Choice
A) bromine with acetic acid.
B) bromine and aqueous hydroxide ion.
C) THF, LDA at -78 °C followed by reaction with bromine.
D) base and methyl bromide.
Correct Answer
verified
Multiple Choice
A) I
B) II
C) III
D) IV
Correct Answer
verified
Multiple Choice
A) Br2/HOAc
B) Br2/KOH
C) Cl2/FeCl3
D) Br2/FeBr3
Correct Answer
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Multiple Choice
A) Only I
B) Only II
C) Only III
D) I and II are equally stable
Correct Answer
verified
Multiple Choice
A) Only I
B) Only II
C) Only III
D) I, II, and III
Correct Answer
verified
Multiple Choice
A) Only I
B) Only II
C) Only III
D) Only I and III
Correct Answer
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Multiple Choice
A) The C=O bond is much stronger than the C=C bond.
B) The C=C bond is much stronger than the C=O bond.
C) The keto form can undergo intramolecular hydrogen bonding.
D) The enol form can undergo intramolecular hydrogen bonding.
Correct Answer
verified
Multiple Choice
A) I
B) II
C) III
D) IV
Correct Answer
verified
Multiple Choice
A) I
B) II
C) III
D) IV
Correct Answer
verified
Multiple Choice
A) I
B) II
C) III
D) IV
Correct Answer
verified
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